Draw a graph showing the variation of decay rate with number of active nuclei.
Draw a graph showing the variation of decay rate with number of active nuclei.
According to formula,
$\mathrm{I}=-\lambda \mathrm{N}$
$\therefore \mathrm{I}=(-\lambda) \mathrm{N}+0$
Form of above equation is like equation of a straight line, $y=m x+c .$ Hence graph of $\mathrm{I} \rightarrow \mathrm{N}$ is a straight line with slope $(-\lambda)$.
Here graph is obtained in $4^{\text {th }}$ quadrant because $N$ is positive and $I$ is negative.
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